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GATE PI 2021 Official Paper

Option 3 : 6

**Concept:**

Here it is asked to calculate cases where the percentage is greater than 10%, so we must ensure that the denominator here is the lowest among the two on a given day.

**Calculation:**

**Given:**

The** percentage** of **time spent** by one student than the other is:

On Sunday = \(\frac{65\ -\ 55}{55}\ \times\ 100\) = 18.18%

On Monday = \(\frac{70\ -\ 45}{45}\ \times\ 100\) = 55.55%

On Tuesday = \(\frac{65\ -\ 55}{55}\ \times\ 100\) = 18.18%

On Wednesday = \(\frac{60\ -\ 50}{50}\ \times\ 100\) = 20%

On Thursday = \(\frac{60\ -\ 55}{55}\ \times\ 100\) = 9.09%

On Friday = \(\frac{35\ -\ 20}{20}\ \times\ 100\) = 75%

On Saturday = \(\frac{60\ -\ 50}{50}\ \times\ 100\) = 20%

From the above-calculated data, **6 days **are there where one student spend a minimum of **10% more** than the other student.